0=4x^2+8x-12

Solution for 0=4x^2+8x-12 equation:

0=4x^2+8x-12

We move all terms to the left:

0-(4x^2+8x-12)=0

We add all the numbers together, and all the variables

-(4x^2+8x-12)=0

We get rid of parentheses

-4x^2-8x+12=0

a = -4; b = -8; c = +12;
Δ = b2-4ac
Δ = -82-4·(-4)·12
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-16}{2*-4}=\frac{-8}{-8}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+16}{2*-4}=\frac{24}{-8}
=-3
$